1. The problem statement, all variables and given/known data A microwave oven produces energy at a rate of P = 1219 W, all in the form of microwaves. When a cup of water is placed into this oven, 64.4% of the microwaves are absorbed by the water. If a cup containing mw = 212 grams of water (227 g equals 8 ounces) starts at temperature Tw = 19.6o C: find t, the time it will take the water to reach its boiling point. 2. Relevant equations Q = mcΔT P = dW/dt 3. The attempt at a solution Heat needed to raise 0.212 kg of water from 19.6 C to 100 C = (0.212)(4186)(100-19.6) Q = 71349.53 Joules Rate of Energy Absorption of Water = (64.4/100)(1219 Joules/sec) = 785 Joules/sec Since water is absorbing heat at 785 Joules per second, in order to absorb 71349.53 Joules altogether, we need: t = 785 J/s / 71349.53 J = 0.011 seconds. Am I approaching the problem incorrectly? Many thanks in advance!