Heat released by combustion of 22.4×10³ L of FeTiH₂

[pollycampos]

Homework Statement

What is the heat released by the complete combustion of 22.4x10^3 litres of FeTiH2 - a fuel used in hydrogen cars -, producing liquid water?

Homework Equations

ΔH°(reaction) = ΔH°f(products) - ΔH°f(reactants)

The Attempt at a Solution

1 mol FeTiH2 - 22,4 L (STP)
x - 22.4x10^3 litres
x = 1000 moles of FeTiH2

I guess the equation for the combustion is:
1000 FeTiH2(g) + 2250 O2(g) = 1000 H2O(l) + 500 Fe2O3(s) + 1000 TiO2(s)

Using the Hess's Law:
ΔH°(reaction) = 1000ΔH°f(H2O,l) + 500ΔH°f(Fe2O3,s) + 1000ΔH°f(TiO2,s)
- 1000ΔH°f(FeTiH2,g) - 2250ΔH°f(O2,g)
ΔH°(reaction) = - 285800 - 824200 - 945000 - 1000ΔH°f(FeTiH2,g) - 0

I'm having trouble finding the heat of formation of FeTiH2. There're some heat of formation around Google, but I haven't found one at 1 atm pressure. So I guess there must be another way to resolve this problem

The answer is - 2.86x10^5 kJ/mol

 

[Borek]

I don't see how FeTiH₂ can be gaseous. I expect solid, so the amount given as a volume (without density) doesn't make much sense.

 

[pollycampos]

Oh yes, my bad But anyway, I can't find the heat of formation