(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

How much heat must be removed when 130 g of steam at 145°C is cooled and frozen into 130 g of ice at 0°C. (Take the specific heat of steam to be 2.01 kJ/kg·K.)

Answer is in kcal.

2. Relevant equations

3. The attempt at a solution

I know steam turns back into water at 100°C

Q1=C1m(deltaT)

Q1=(2010 J//kg·K)(.13kg)(418.15K-373.15K)

In the second part, instead of using the specific heat of steam, I used the specific heat of water= 4.186 joule/gram °C

Q2=C2m(deltaT)

Q2=(4.186 J/g·°C)(130g)(100°C)

I then added Q1 to Q2 and came up with an answer in Joules.

1 joule = 0.000239005736 kilocalories

But my answer is wrong. Anyone see what I missed? Probably a conversion issue.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Heat Removed

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