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## Homework Statement

A 6.00-kg piece of solid copper metal at an initial temperature

*T*is placed with 2.00 kg of ice that is initially at -20.0C. The ice is in an insulated container of negligible mass and no heat is exchanged with the surroundings. After thermal equilibrium is reached, there is 1.2 kg of ice and 0.80 kg of liquid water. What was the initial temperature od the piece of copper?[/B]

## Homework Equations

Q=mcΔT

Q=mL (L in this case is the heat of fusion)

ΣQ=0[/B]

## The Attempt at a Solution

Qcopper= 6(390)(Tf-

*T*)

Qice=2(2100)(0-(-20))=8400J (heat required to raise the temperature of the ice to 0C)

Qwater=.8(334x10^3)=26400J (heat required to melt .8 kg of ice)

applying

**ΣQ=0:**

6(390)(Tf-

6(390)(Tf-

*T*) + 8400+26400=0Tf= would have to be 0c because we still have some ice left.

solve for

*T:*

T=118.974C

T

The correct answer is 150C

what did I do wrong?[/B]

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