A cylindrical rod of stainless steel is insulated on its exterior surface except for the ends. The steady-state temperature distribution is T(x) = a-bx/L, where a = 305 K and b =10 K. The diameter and length of the rod are D = 20 mm and L =100 mm, respectively. Determine the heat flux along the rod, Hint: The mass of the rod is M = 0.248 kg. T(x) = 305 - 100x. dT(x)/dx = -100. I know that heat flux is modeled by Fourier's Law for conduction: qx'' = -k*dT/dx. What I'm having trouble finding is the conductivity k and I'm wondering whether it has something to do with the mass of the rod, although I am not seeing the connection here. Thanks.