1. The problem statement, all variables and given/known data A copper calorimeter with mass 0.1 kg contains 0.15 kg of water and 0.012 kg of ice in their equilibrium at normal atmospheric pressure(0 degrees Celsius). If 0.5 kg of lead at 200 Celsius is dropped in calorimetr, what is the final temperature?( consider the close system so no temperature lost). 2. Relevant equations Cw*Mw*(Tf-Ti)=Cice*Mice*(Tf-Ti)=Ccop*Mcop*(Tf-Ti)=Clead*Mlead*(Ti-Tf) 3. The attempt at a solution I'm not sure if i have to consider the latent phase, so any help would be appreciated. Thank you.