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1. Homework Statement
there is 70kg/h of feed going into the evaporator, of which 11% is solids, so that's 7.7kg/h of solids, and so 62.3kg/h of liquid in the feed.
so now how do I calculate the amount of water in the vapour stream and the amount of solids in the product? I intially thought you just work out 35% of the 70kg/h feed for the product, since it says there is 35% solids in the product, but this is not correct.
Can someone please show/explain how to work out the flow rate of the product tream and vapour stream.
Thank you.
I have attached a diagram, for this question, I am stuck on how to calculate the flow rate.In an experimental study, slurry is being concentrated in a continuous vacuum evaporator at a
rate of 70 kg/hour. The feed material has a temperature of 16°C and a total solids content of
11%. A product of 35% total solids is withdrawn at a temperature of 42°C. The evaporator
operates at a pressure of 7.375 kPa and removes vapour at 40°C. This vapour is fed to a
condenser, from which condensate at 40°C is removed.
i) Using a mass balance table over the evaporator, calculate the flowrates of the
product and vapour streams.
there is 70kg/h of feed going into the evaporator, of which 11% is solids, so that's 7.7kg/h of solids, and so 62.3kg/h of liquid in the feed.
so now how do I calculate the amount of water in the vapour stream and the amount of solids in the product? I intially thought you just work out 35% of the 70kg/h feed for the product, since it says there is 35% solids in the product, but this is not correct.
Can someone please show/explain how to work out the flow rate of the product tream and vapour stream.
Thank you.
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