1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Heat Transfer

  1. Jan 12, 2016 #1
    1. The problem statement, all variables and given/known data
    A thick wall cylinder having a thermal conductivity of 60W/mK has a 75mm inner diameter and is 2.5mm thick. The pipe carries water at 90 degrees celsius inside and the outside is surrounded by air at 20 degrees celsius.

    The heat transfer coefficients inside and outside the hot water pipe are 500W m2 K and 35 W m2 K respectively. Natural convection can be ignored.

    Calculate the heat loss in W per unit length of the pipe
    2. Relevant equations

    q= K Delta U T1-T2/r1-r2 = T1-T2/r2-r/Kal

    Alm = 2Pie Lr2- 2Pie Lr1/Ln(2(2{PieLr2/2pieLr1


    = A2-A1/ln(A2/A1)


    3. The attempt at a solution

    q = 90-20/0.03875-0.037
    60 * (2Pie x 1 x 0.03875- 2Pie x 1 x 0.03875)/
    ln (2Pie x 1 x0.3875/2Pie x 1 x0.3875/2Pie x 0.3875
     
  2. jcsd
  3. Jan 12, 2016 #2
    Your equations are unreadable. Please use the symbols provided with the ∑ sign on the tool bar, or use Latex. There is a LaTex tutorial available on our sight.

    Regarding your calculations, you seem to have omitted the heat transfer resistance on the air side and on the fluid side, which are in series with the pipe wall. Also, for such a thin wall, there is no need to use the log-mean.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Heat Transfer
  1. Heat Transfer (Replies: 1)

  2. Heat Transfer (Replies: 0)

  3. Heat Transfer (Replies: 0)

  4. Heat Transfer (Replies: 2)

Loading...