Heat Transfer

  • Thread starter encorelui2
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  • #1

Homework Statement



See attached figure. Ta>Tb. Show that the rate of energy conducted dQ/dt is 2*pi*L*k((Ta-Tb)/Ln(b/a))

Homework Equations




The Attempt at a Solution


I seem to be lost at deriving an equation for the medium area, A.
I understand the tansfer from low temp area to high. Pcond. is proportional to change in temp from H to L temp areas. I have attached my attempt at a soln.
 

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Answers and Replies

  • #2
TSny
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This forum requires you to show some work towards a solution before we can help you.

What have you learned about heat conduction that you think might be relevant? Do you know how to calculate the rate of heat flow through a thin slab of material? Do you know any formulas that might be helpful?
 
  • #3
TSny
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Which parts of your notes shown below apply specifically to this problem?
upload_2017-2-12_21-32-35.png
 
  • #4
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If the radial temperature gradient is dT/dr, what is the rate of heat flow through the cylindrical surface at radius r (inside the conductor)?
 
  • #5
gneill
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@encorelui2 : An image of class notes does not comprise a solution attempt, particularly an image that is essentially illegible due to poor image quality and small handwriting (your personal handwriting may be clear as day to you, but it's close to a secret code to others when it's tiny and fuzzy and low contrast). Please provide an acceptable solution attempt or at least describe what approaches you've tried. If you use an image, be sure number every equation on the page so that helpers can refer to them in their responses.

If your images are not clear enough to read then you need to type in your attempt. Text-formatted math can be rendered using the icon tools in the edit panel header or using LaTeX syntax. It's much easier for helpers to read, quote, and comment on typed-in content and experience shows that you'll more, and more timely help responses that way.

Note that without a valid solution attempt your thread is in danger of being removed. See:
Hey! I posted here but now it's gone!
 
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