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**Here is a problem on "Heating Effect Of Current".I can't understand a part of it.**

__INTRODUCTION:__**"A battery of emf E and internal resistance r is supplying current to an external resistance R.(a)Show that the power dissipated in R will be maximum when R=r.(b)What is the maximum power?(c)What would happen if the battery is shorted?"**

__EXACT PROBLEM:__**a)The current in the circuit is i=E/(R+r).Power dissipated is P=(i^2)r.Now putting the value of i, we find that P will be maximum when denominator is minimum,i.e. (R-r)^2 is 0. So, R=r.**

__WHAT MY BRAIN SUGGESTED:(__(b)Putting r in place of R in the power equation, we get maximum power as (E^2)/4r.

(c)

*The word "shorted" is not yet registered in the PHYSICS part of my brain .BRAIN CANNOT SUGGEST ANYTHING.SORRY.*

*****ERROR*******What does "battery is shorted" mean?And what would happen if the battery is shorted?**

__CONFUSION:__**Physics Forums say that it is necessary to show that one has tried a particular problem in order to be answered.But what can one do if he cannot understand the meaning of a term?(I don't know what exactly "shorted" is).How will i prove that i've really tried part (c)?Nevertheless, i've tried to show that i know the other things of "Heating Effect Of Current".If you still don't believe me i have nothing to say. But if you do help me, thank you in advance.**

__CONCLUSION:__