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Heating water using water

  1. Apr 9, 2008 #1
    1. The problem statement, all variables and given/known data

    How can you heat [tex]1 \,\mathrm{kg}[/tex] mineral water which is at a temperature of [tex]0 \,{}^\circ \mathrm{C}[/tex] to at least [tex]60 \,{}^\circ \mathrm{C}[/tex] with using [tex]1 \,\mathrm{kg}[/tex] plain water at a temperature of [tex]100 \,{}^\circ \mathrm{C}[/tex]?

    2. Relevant equations

    [tex]\Delta Q = mc\Delta T[/tex]

    3. The attempt at a solution
    [tex]\underbrace{(1000 g)(4.18~J/g~C)(60~C)}_{\text{heat gained}} = \underbrace{m(4.18~J/g~C)(100~C - 60~C)}_{\text{heat lost}}[/tex]
    But then [tex]m>1000 g[/tex]. So I really don't know how to do it. There should be a nasty trick in it.
  2. jcsd
  3. Apr 9, 2008 #2
    Check your cp's. They should be different given the temperature difference and though subtle, material difference.
  4. Apr 10, 2008 #3
    Thanks but don't think that there are so much difference between them. Any other ideas?
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