# Heating water using water

1. Apr 9, 2008

### dogcat

1. The problem statement, all variables and given/known data

How can you heat $$1 \,\mathrm{kg}$$ mineral water which is at a temperature of $$0 \,{}^\circ \mathrm{C}$$ to at least $$60 \,{}^\circ \mathrm{C}$$ with using $$1 \,\mathrm{kg}$$ plain water at a temperature of $$100 \,{}^\circ \mathrm{C}$$?

2. Relevant equations

$$\Delta Q = mc\Delta T$$

3. The attempt at a solution
$$\underbrace{(1000 g)(4.18~J/g~C)(60~C)}_{\text{heat gained}} = \underbrace{m(4.18~J/g~C)(100~C - 60~C)}_{\text{heat lost}}$$
But then $$m>1000 g$$. So I really don't know how to do it. There should be a nasty trick in it.

2. Apr 9, 2008

### Kilopilo

Check your cp's. They should be different given the temperature difference and though subtle, material difference.

3. Apr 10, 2008

### dogcat

Thanks but don't think that there are so much difference between them. Any other ideas?