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**1. Homework Statement**

How can you heat [tex]1 \,\mathrm{kg}[/tex] mineral water which is at a temperature of [tex]0 \,{}^\circ \mathrm{C}[/tex] to at least [tex]60 \,{}^\circ \mathrm{C}[/tex] with using [tex]1 \,\mathrm{kg}[/tex] plain water at a temperature of [tex]100 \,{}^\circ \mathrm{C}[/tex]?

**2. Homework Equations**

[tex]\Delta Q = mc\Delta T[/tex]

**3. The Attempt at a Solution**

[tex]\underbrace{(1000 g)(4.18~J/g~C)(60~C)}_{\text{heat gained}} = \underbrace{m(4.18~J/g~C)(100~C - 60~C)}_{\text{heat lost}}[/tex]

But then [tex]m>1000 g[/tex]. So I really don't know how to do it. There should be a nasty trick in it.