# Heating water using water

1. Homework Statement

How can you heat $$1 \,\mathrm{kg}$$ mineral water which is at a temperature of $$0 \,{}^\circ \mathrm{C}$$ to at least $$60 \,{}^\circ \mathrm{C}$$ with using $$1 \,\mathrm{kg}$$ plain water at a temperature of $$100 \,{}^\circ \mathrm{C}$$?

2. Homework Equations

$$\Delta Q = mc\Delta T$$

3. The Attempt at a Solution
$$\underbrace{(1000 g)(4.18~J/g~C)(60~C)}_{\text{heat gained}} = \underbrace{m(4.18~J/g~C)(100~C - 60~C)}_{\text{heat lost}}$$
But then $$m>1000 g$$. So I really don't know how to do it. There should be a nasty trick in it.