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Heaviside fcn

  1. Feb 8, 2006 #1
    can someone please help me graph this function:
    u(t)-2u(t-2)+u(t-5) where u(t) is heaviside fcn.
    i got that it's 1 from 0<t<2 and 1>5 but i don't think that's right but don't know what to do with the 2 in 2u(t-2). thank you.
     
  2. jcsd
  3. Feb 8, 2006 #2

    Hurkyl

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    You multiply the values of u(t-2) with it.
     
  4. Feb 8, 2006 #3
    well, obviously but how would that change the graph? would it change the interval, amplitude, or both? can someone please be more specific in their answer. an example, anything.
     
  5. Feb 8, 2006 #4

    Hurkyl

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    Well, I'm trying to point out that there is nothing unusual going on here: it's just straight arithmetic. I think you're making the problem much harder than it really is: all you have to do is compute the value on each piece.
     
  6. Feb 9, 2006 #5

    HallsofIvy

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    If you multiply any function by 2, what happens to its value?

    In particular, the Heaviside function only has values of 0 and 1. Surely you can multiply 0 and 1 by 2!
     
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