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Heaviside function

  1. May 6, 2010 #1
    What is H(-x)? Is it 1 if x < 0, 0 if x [tex]\geq[/tex] 0. If so what is the Fourier transform of H(-x)exp(x)?
     
  2. jcsd
  3. May 6, 2010 #2

    Mute

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    Homework Helper

    By definition, H(x) is 0 if x < 0, 1 if x > 0, so setting x -> -x gives H(-x) is 0 if x > 0, 1 if x < 1. By inspection, you should be able to relate H(-x) to H(x), by H(-x) = 1 - H(x), which will help you with your Fourier transform.
     
  4. May 6, 2010 #3
    Sweet.
    My Fourier transform is f(w) = 1/(1-iw)
     
  5. May 7, 2010 #4
    So is the fourier transform of H(x)exp(-2x) + H(-x)exp(x)
    f(w) = 1/(2+iw) + 1/(1-iw)?
     
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