# Heaviside function

1. May 6, 2010

### squenshl

What is H(-x)? Is it 1 if x < 0, 0 if x $$\geq$$ 0. If so what is the Fourier transform of H(-x)exp(x)?

2. May 6, 2010

### Mute

By definition, H(x) is 0 if x < 0, 1 if x > 0, so setting x -> -x gives H(-x) is 0 if x > 0, 1 if x < 1. By inspection, you should be able to relate H(-x) to H(x), by H(-x) = 1 - H(x), which will help you with your Fourier transform.

3. May 6, 2010

### squenshl

Sweet.
My Fourier transform is f(w) = 1/(1-iw)

4. May 7, 2010

### squenshl

So is the fourier transform of H(x)exp(-2x) + H(-x)exp(x)
f(w) = 1/(2+iw) + 1/(1-iw)?