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## Main Question or Discussion Point

We know light made up of photons which is massless, but why it can absorbed by black hole? Is it becuz the Einstein's relativity about every object can curve time space

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- Thread starter Muhammad Valent
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We know light made up of photons which is massless, but why it can absorbed by black hole? Is it becuz the Einstein's relativity about every object can curve time space

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LIght doesn't have mass but it has momentum and it moves along geodesics just like everything else that is not being acted on by outside forces.We know light made up of photons which is massless, but why it can absorbed by black hole? Is it becuz the Einstein's relativity about every object can curve time space

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But Accord to momentum itu also need mass "p =mv which is nonLIght doesn't have mass but it has momentum and it moves along geodesics just like everything else that is not being acted on by outside forces.

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Nugatory

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I can also write the momentum of light as p = ħk. So where is the "mass" requirement there?But Accord to momentum itu also need mass "p =mv which is non

Please note that even before 1900, i.e. before Special Relativity and Quantum Mechanics, classical theory of electromagnetism and light already know about the momentum of light, all without even considering the picture that light consist of "photons" or the possibility that it has mass. So even back then, there was zero need to introduce mass to account for the momentum of light that they had observed. This means that just because something has a momentum, it doesn't

BTW, in solid state physics, we also designate a crystal momentum as p=ħk without invoking any mass. So this isn't specific just to light. It means that there is a more universal definition of momentum than what you already know.

Zz.

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Consider that photons have a defined energy and then apply energy mass equivalence. This is a bit of hand waving, but should be adequate to answer your original question.

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You cannot simply "apply" the mass-energy equivalence, because the "mass" in that is the rest/invariant mass. It will also mess up the full relativistic energy equation, because now, the "m" in E

Consider that photons have a defined energy and then apply energy mass equivalence. This is a bit of hand waving, but should be adequate to answer your original question.

Zz.

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RPinPA

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Yes. That was precisely the point that made Einstein famous to the general public. Newton's theory of gravitation predicted light, with no mass, will not be affected by gravity. Einstein predicted that light, because it follows geodesics in distorted space-time,Is it becuz the Einstein's relativity about every object can curve time space

Not merely in the actual fact, but the amount to which it is bent by gravity is precisely predicted by general relativity. A lot of people seem to miss the fact that when physics makes predictions, they have actual numerical values.

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Can you provide a corresponding calculation? In case of light deflection by a central mass I get half the effect compared to relativity.Newton's theory of gravitation predicted light, with no mass, will not be affected by gravity.

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... Newton's theory of gravitation predicted light, with no mass, will not be affected by gravity.

I'm puzzled. How could you do a calculation in Newtonian physics that says light, being massless, is affected by gravity at anything other than zero effect? How does Newtonian gravity affect something that has no mass?Can you provide a corresponding calculation? In case of light deflection by a central mass I get half the effect compared to relativity.

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The gravitational force is zero but not the effect. Keep in mind that the force required to accelerate a massless object is zero too in classical mechanics. Calculating the resulting effect is quite easy:How could you do a calculation in Newtonian physics that says light, being massless, is affected by gravity at anything other than zero effect?

According to Newton's law of gravitaton, the force acting on an object with mass m in the gravitational field of a central mass M is

[itex]F = - \frac{{M \cdot G \cdot r}}{{\left| r \right|^3 }} \cdot m[/itex]

According to the second law of motion the resulting acceleration is

[itex]\ddot r = \frac{F}{m} = - \frac{{M \cdot G \cdot r}}{{\left| r \right|^3 }} \cdot \frac{m}{m}[/itex]

If light is assumed to be massless (that's not obvious in classical mechanics) L'Hôpital's rule results in

[itex]\mathop {\lim }\limits_{m \to 0} \ddot r = - \frac{{M \cdot G \cdot r}}{{\left| r \right|^3 }}[/itex]

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