(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex] f(t) = \left\{ \begin{array}{rcl}

5sin(t) & \mbox{for}

& 0 < t < 2\pi \\

0 & \mbox{for} & t > 2\pi

\end{array}\right. [/tex]

Now, the problem is about rewriting f(t). My friend and I decided that it had to be

[tex] \dfrac{10 - 5e^{-2\pi s}}{s^2 + 1} [/tex]

However, the answer turned out to be

[tex] \dfrac{5 - 5e^{-2\pi s}}{s^2 + 1} [/tex]

Any help towards understanding this would be greatly appreciated! (We assumed they divided the first part by [tex]2\pi[/tex] when we extended [tex]5sin(t)[/tex] to [tex]5sin(t - 2\pi)[/tex], but we don't understand why!)

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Heavyside function for Sine

**Physics Forums | Science Articles, Homework Help, Discussion**