- #1
nicolayh
- 6
- 0
Homework Statement
[tex] f(t) = \left\{ \begin{array}{rcl}
5sin(t) & \mbox{for}
& 0 < t < 2\pi \\
0 & \mbox{for} & t > 2\pi
\end{array}\right. [/tex]
Now, the problem is about rewriting f(t). My friend and I decided that it had to be
[tex] \dfrac{10 - 5e^{-2\pi s}}{s^2 + 1} [/tex]
However, the answer turned out to be [tex] \dfrac{5 - 5e^{-2\pi s}}{s^2 + 1} [/tex]
Any help towards understanding this would be greatly appreciated! (We assumed they divided the first part by [tex]2\pi[/tex] when we extended [tex]5sin(t)[/tex] to [tex]5sin(t - 2\pi)[/tex], but we don't understand why!)
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