# Homework Help: Height of bullet

1. Sep 23, 2006

### needhelp83

I can't figure out if I set this problem up correctly. Any help?

The muzzle speed of a 22-caliber bullet fired from a rifle is 360 m/s. If there were no air resistance, how high would this bullet rise when fired straight up?

v^2=intial v^2+2ay
y=v^2-initial v^2/2a=(0-(360 m/s)^2)/2(-9.80 m/s^2)=6,612 m

The maximum height reached is 6,612 m.

2. Sep 23, 2006

### QuantumKing

No, could you imagine a bullet being shot in the air and reaching a maximum heaight of 6.6 meters? lol:P

First find the time it takes...360/9.8...then it should be relatively simple to figure out

3. Sep 23, 2006

### FunkyDwarf

No, 6km is correct. Youll find a general term for what you described above as:

$$h = y(peak) = \frac{V(y)^2}{2g}$$

Where V(y) is the initial vertical component of the velocity