- #1

- 15

- 0

So here is what I have done:

Tan theta= 50/x

Theta = arctan 50/x

Tan (theta + beta) = 50 + h / x

(theta + beta) = arctan 50 + h / x

theta = arctan 50 + h / x – arctan 50 / x

theta ‘ = 1/ 1 + (50 + h / x)^2 (-50 – h/ x^2) – 1/ 1 + (50/x)^2 (-50/x^2)

= -50 – h / x^2 + (50 + h)^2 + 50 / x^2 + 50^2 = 0

50 / x^2 + 50^2 = 50 + h / x^2 + (50 + h)^2

I hope you can understand, I can't get a triangle on here to show you so I hope you can follow along.

Once I get to the last line, i'm not sure what to do. I've tried plugging 60 in for x but i don't think I get a correct answer.