Hey guys, im new here, i was wondering if you could help me solve the following problems ok...A stone is thrown vertically upward at a speed of 48.70 m/s at time t=0. A second stone is thrown upward with the same speed 4.390 seconds later. At what time are the two stones at the same height? now i know the height where they meet is: 7.159s, but i cant solve the other part: At what height do the two stones pass each other? What is the downward speed of the first stone as they pass each other? any help would be appreciated thanks!