(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A .250 kg block on a vertical spring with a spring constant of 5.00 x 10(3) N/m is pushed downward, compressing the spring .100 m. When released, the block leaves the spring and travels upward vertically. How high does it rise above above the point of release?

Mass = .250 kg

Distance = .100m

Spring Constant/K = 5.00 x 10(3) N/m or 5000 N/m

2. Relevant equations

Have to find EPE I think, EPE = 1/2 K(^x)2....the ^ is a triangle which in this equation is change in length.

Maybe use mgh

3. The attempt at a solution

I got EPE which was 25. I think that to find h you can use formula mgh. I forgot how to do this but I recall doing something like (.250)(9.81)(h), 2.45(h), and you take the square root of 2.45 and that is how you get h. Then in this problem h would = 1.60m. I really think this is wrong but it was all I could think of.

Can someone please help me find the height? Or if I have the correct method please reply and tell me I did it right(don't think I did though)

Thank You

~Patrick

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# Homework Help: Height with EPE question.

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