Hel again

  • Thread starter meczs
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  • #1
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http://www.pa.msu.edu/courses/1997spring/PHY232/lectures/kirchoff/examples.html" [Broken]

how can you solve my circuit (that i attached) using that procedure... in that site.. i saw it last week... thats the shortest way i seen... can you help me.. thankss
 

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Answers and Replies

  • #2
mukundpa
Homework Helper
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Did you learned Kirchoff's laws ? Show your work.
 
  • #3
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yah i learned it.... but it is the longest solution.... i hate that.... i want the shortest method.... that i found in that site.. can you solve it using that method?

i put the answer @ my attachment

here is the solution i've learned

@node B
i1 + 12 - i3 = 0
i3 = i1 + i2 that is for eq. 1

@loop abefa
E1 + E2 -15i1 +26i2
40v + 50v -15i1 +26i2
90 + 26i2 / 15i1 eq. 2

@loop bcdeb
-E2 -E3 -26i2 -37i3
-50 -60 -26i2 -37i3
-110 -37i3 / 26i2 eq. 3

that is the my sample solution ive learnd.... but it is not finish.. like i said; that is the longest solution.... hoping that you understand it.....

(sorry bad grammar)
 
  • #4
berkeman
Mentor
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You need to set the second two things equal to zero to make them equations. That gives you 3 equations and 3 unknowns -- just solve away. There's not really a quicker way to solve it that I know of, unless you mean using determinants to solve the simultaneous equations. In this circuit, the equations are simple enough that solving with determinants won't save you any time.
 

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