1. The problem statement, all variables and given/known data The height of a helicopter above the ground is given by h = 2.60t3, where h is in meters and t is in seconds. At t = 2.10 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? 2. Relevant equations Y=ViT - (1/2)gt^2 3. The attempt at a solution h=(2.60)(2.10)^3 24.0786=0t-(1/2)(9.8)t^2 Thank you.