There's a block of mass M that's pulled up an incline by a force T. The block starts from rest and is pulled a distance L by the force T. The incline, which is frictionless, makes an angle (a) with respect to the horizontal. 1) Write down the work done by force T. That would just be W = T*L right? ...Even though net work would be W = TL - mg sin (a) 2) Calculate the potential energy of the block as a function of the position L. U = mgh = mgLsin(a), right? 3) From the work and the potential energy calculate the kinetic energy of the block as a function of position L. Okay... so since the force is conserved, KE + PE + W = 0, right?? So KE = -W - PE = - (TL - mg sin (a)) - mgLsin(a)) Is that correct or no?? 4) Calculate the acceleration of the block, a, as a function of position L. Calculate the velocity from the acceleration and kinetic energy as a function of position. Show that the kinetic energies calculated in these two ways are equivalent. I can't get this part to work. I put acceleration = F/M = (T-mg sin (a)) / m but how do I get it in terms of L? And how do I integrate the acceleration function with respect to L?? Thank you! All help is greatly appreciated!!