- #1

- 91

- 0

f(x) = x^2 - 5x + 3

and

H(x) = -x

Is H(x) an antiderivative? how do I solve this?

2) Find the area of the region bounded by the graphs of

x - y^2 + 2y + 4 = 2

and

2y - 2 - x = 0

so, x = y^2 - 2y - 2 and x = 2y - 2

I, then, substitute the x: y^2 - 2y -2 = 2y -2 and got y^2 - 4y=0

so, y=0,4

then I solve with antiderivatives and got -32/3 but the correct answer is

-16/3