[HELP]- Determine the Resultant of the Force System.

  • Thread starter Dellis
  • Start date
  • #51
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Those two are equivalent. One just factors out the negative sign...

CS
Sorry I just got a bit confused, he presented it in a way not shown to me in the book but yeah it is the same....

post after this one has my calculations done
 
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  • #52
stewartcs
Science Advisor
2,177
3
Sorry I just got a bit confused, he presented it in a way not shown to me in the book but yeah it is the same....

[tex]\Sigma[/tex] F= -100 lb - 700 lb - 160 lb= -960



R = -(100 + 700 + 160)=-960
No problem...that's why we are here...

CS
 
  • #53
90
0
No problem...that's why we are here...

CS
I appreciate it, I learned more reading these forums then using this 150 dollar buck, thanks again.

Ok so here the finish line right?....

ΣF= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100(0) - 700(8) - 160(8 + 4)= - 7520 lb


X(bar) =ΣM/R.

-7520 lb/-960lb= 7.83 lb
 
  • #54
stewartcs
Science Advisor
2,177
3
Ok so here the finish line....

[tex]\Sigma[/tex] F= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100(0) - 700(8) - 160(8 + 4)= - 7520 lb


X(bar) =ΣM/R.

-7520 lb/-960lb= 7.83 lb
Check your units...

CS
 
  • #55
90
0
Check your units...

CS
Woah I almost forgot about that lil detail, so this is it right.


ΣF= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100 lb(0) - 700 lb(8) - 160lb/ft(12)= -7520 lb/ft


X(bar) =ΣM/R

-7520 lb/ft (divided by) -960lb= 7.83 ft
 
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  • #56
stewartcs
Science Advisor
2,177
3
Woah I had forgot about that lil detail, so it is like this

ΣF= -100 lb - 700 lb - 160 lb= -960 lb

ΣM = -100 lb(0) - 700 lb(8) - 160lb/ft(12)= -7520 lb/ft


X(bar) =ΣM/R.

-7520 lb/ft (divided by) -960lb= 7.83 ft
Correct.

CS
 
  • #57
90
0
Correct.

CS
Yes!:), thank you all for the guidance in regards to this problem, see now I can do these type of exercises since I understand the process, that is my problem I need to get familiar with the processes.


Like I said before I do have two other problems I tried doing by myself and I need them checked/corrected, I will make a new thread since this one is too much already, hopefully you can provide further guidance for those two :).
 
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