1) A plank of mass 2.5 kg and length 2 meters is resting horizontally on two wedges. The first is at one of the ends and the other is a distance 0.3 meters from the second end. If a mass of 0.2 kg is placed on this second edge, what is the force (in Newtons) acting on the second wedge. Here's what I did: T1=F1(0) = 0 T2=F2(1.7) T(mass)=-(0.2*9.81*2) = -3.924 T(plank)=-(2.5*9.81*(2/2)) = -24.525 sum of torque = F1(0) + F2(1.7) - 3.924 - 24.525 = 0 so, F2=16.73 Newtons but the correct answer is 1.71 Newtons. Where did I go wrong? 2) The mass of the earth is 6.0E24 kg and its radius is 3950 miles. Assuming that the earth is a uniform sphere, its angular momentum (in Joule. Secs) is aE+33 where a is? I = (2/5) MR^2 ---> (2/5)(6.0E24)(6355550meters)^2 = 9.694E37 L = Iw ---> (9.694E37)((2pi)/86400) = 7.0499E33 which makes a=7.050 but the correct answer is 6.970. (I did not round anything either.) What did I do wrong? Please help. Thanks!