1) Give the conditions for the equilibrium of an extended object. An extended object is at equilibrium when no force is acting on it. 2) A uniform ladder of length 6.0m and mass 12.0kg is placed against a smooth vertical wall. The ground is rough. a) Calculate the force on the ladder from the wall. vertical forces = 0 = N1 - W so N1 = 117.72 horizontal forces = 0 = F - N2 Total Torque = 0 0 = F(0) + N1(0) + (12*9.81*cos60*(6/2)) - (N2sin60(6)) so, N2 = 33.98 Newtons b) Find the minimum coefficient of friction of the ground. F - 33.98 = 0 ---> F=33.98 friction > F1/N1 so, coefficient of friction=33.98/117.72 ----> 0.289 Are my answers correct? If not, what did I do wrong. Please help. Thanks!