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1. The problem statement, all variables and given/known data

An archer shoots an arrow horizontally at a target 12 m away. The arrow is aimed directly at the center of the target, but it hits 52 cm lower. What was the initial speed of the arrow? (Neglect air resistance.)

2. Relevant equations

well im just dumb founded on this problem could some one please help me.

the equation i was given is : y= h - .5at^2 and x=vo*t so we then know t= x/vo

second part of the equation is y=h -.5 a(x/vo)^2

then vox* the square root of (a/2)*(x^2/h-y)

3. The attempt at a solution

the problem im having is finding all the right data to complete the problem. We know x = distance which then = 12 and h(height) = 52cm or .52m

so in the first equation when it says y=h-.5at^2 and x=vo*t we need to find t so we can subsitute it for t^2 in the 1st equation. so the equation is t=x/vo and we get t=12/vo i dont need the answer to the problem i just need help finding what t is so i can solve it for myself. can you please explain how to find vo or whatever i need to find to start this problem. ive been working on it for a while now and i cant seem to come up with any answers.

Thanks alot to anyone who can be a hand

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# Homework Help: Help finding the initial speed

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