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Hi, I am having trouble finding x for the following exquation:

2

Any help on solving it would be much apprecitated.

2

^{x}=16^{-3/4}* sqrt(2)Any help on solving it would be much apprecitated.

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- Thread starter Matrix
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- #1

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2

Any help on solving it would be much apprecitated.

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- #2

dduardo

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2^x = 16^(-3/4) * sqrt(2)

x*ln(2) = ln(16^(-3/4) * sqrt(2) )

x = ln(16^(-3/4) * sqrt(2) ) / ln(2)

- #3

jcsd

Science Advisor

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reduce it further to:

x = -2.5

x = -2.5

- #4

dduardo

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jcsd, your i see you changed your reduction. The previous one was obviously wrong.

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Is it possible to find x not using logs?

- #6

jcsd

Science Advisor

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Duardo: No, it was perfectly correct.

- #7

dduardo

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yes.Originally posted by Matrix

Is it possible to find x not using logs?

you can convert 16 to a base 2

16^(-3/4) = (2^4)^(-3/4) = 2^(-3)

therefore

2^x = 2^(-3) * 2^(1/2)

2^x = 2^(-5/2)

x = -2.5

- #8

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This is probably off topic, but don't you just love logs?

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