Help finding x

  • Thread starter Matrix
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  • #1
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Hi, I am having trouble finding x for the following exquation:
2x=16-3/4 * sqrt(2)

Any help on solving it would be much apprecitated.
 
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Answers and Replies

  • #2
dduardo
Staff Emeritus
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why don't you use logs.

2^x = 16^(-3/4) * sqrt(2)

x*ln(2) = ln(16^(-3/4) * sqrt(2) )

x = ln(16^(-3/4) * sqrt(2) ) / ln(2)
 
  • #3
jcsd
Science Advisor
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reduce it further to:

x = -2.5
 
  • #4
dduardo
Staff Emeritus
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jcsd, your i see you changed your reduction. The previous one was obviously wrong.
 
  • #5
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Is it possible to find x not using logs?
 
  • #6
jcsd
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Duardo: No, it was perfectly correct.
 
  • #7
dduardo
Staff Emeritus
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Originally posted by Matrix
Is it possible to find x not using logs?
yes.

you can convert 16 to a base 2

16^(-3/4) = (2^4)^(-3/4) = 2^(-3)

therefore

2^x = 2^(-3) * 2^(1/2)

2^x = 2^(-5/2)

x = -2.5
 
  • #8
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This is probably off topic, but don't you just love logs?
 

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