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**urgent help for biomechanics question**

the question that im not sure of is:

A body of mass 9.4 kg initially moving in a straight line at 3.7 m/s is acted on by an accelerating force of 36.5 N (in the same direction as initial motion) for 1.32 seconds Calculate the velocity of the body at the moment the applied force ceases. Express the units in symbol form in the space provided.

when i sorted it out i found acceleration first a=0-3.7/1.32= -2.80

then i had to find final

vf= 3.7+-2.80 x 1.32= my calculator came with 4.e-03 which is 0.004, however i did it another way and made acceleration positive and got 7.40.

but the one thing that im concerned is that i have not inputed the newtons and kilos in this equation :(

your help is greatly appreciated :)