- #1
yaho8888
- 62
- 0
Homework Statement
0.2500 g sample of an Aℓ-Zn alloy reacts with HCℓ to form hydrogen gas:
Aℓ(s) + 3H+(aq) → Aℓ3+(aq) + 3/2H2(g)
Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)
The hydrogen produced has a volume of 0.147 L at 25°C and 755 mm Hg. What is the
percentage of zinc in the alloy?
Homework Equations
PV=NRT
The Attempt at a Solution
Frist I start out finding the number of moles of Hydrogen gas produced by using PV=NRT
N=((.993atm)(.147L))/((.0821)(298K))= .00596 mol of H2
1mol of Al = 26.98g
1mol of Zn = 65.93g
now what should I do?
Help please.