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Help for force problem

  1. Sep 22, 2004 #1
    An Object acted on by three forces moves with constant velocity. One force acting on the object is in the positive x direction and has a magnitude of 6.5N; a second force has a magnitude of 4.4N and points in the negative y direction. Find the direction and magnitude of the third force acting on the object.

    (6.5^2 + 4.4^2)^1/2

    Am having problems getting the answer for the direction. I used
    Tan^- (4.4/6.5)= but I get .59507

    and the answer in the back of the book is 34.1 for the direction. What am I doing wrong?please help
  2. jcsd
  3. Sep 22, 2004 #2
    Your calculator is in radians.:)
  4. Sep 22, 2004 #3
    thanks for the help
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