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An Object acted on by three forces moves with constant velocity. One force acting on the object is in the positive x direction and has a magnitude of 6.5N; a second force has a magnitude of 4.4N and points in the negative y direction. Find the direction and magnitude of the third force acting on the object.

answer-

(6.5^2 + 4.4^2)^1/2

=7.9N

Am having problems getting the answer for the direction. I used

Tan^- (4.4/6.5)= but I get .59507

and the answer in the back of the book is 34.1 for the direction. What am I doing wrong?please help

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# Homework Help: Help for force problem

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