Help!-Force vectors!

  • Thread starter Scorpiogrl
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  • #1

Homework Statement



Four 9.5 kg spheres are located at the corners of a square of side 0.60 m. Calculate the magnitude and direction of the gravitational force on one sphere due to the other three.


Homework Equations



F=G(mass of #1)(mass of #2)/r^2
F=G(mass of #1)(mass of #3)/r^2
F=G(mass of #1)(mass of #2)/r^2
For #3 take Fsin(45)=x value
For #3 x value=y value

x and y components added
F=squareroot(x^2+y^2)


The Attempt at a Solution

 

Answers and Replies

  • #2
PeterO
Homework Helper
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Homework Statement



Four 9.5 kg spheres are located at the corners of a square of side 0.60 m. Calculate the magnitude and direction of the gravitational force on one sphere due to the other three.


Homework Equations



F=G(mass of #1)(mass of #2)/r^2
F=G(mass of #1)(mass of #3)/r^2
F=G(mass of #1)(mass of #2)/r^2
For #3 take Fsin(45)=x value
For #3 x value=y value

x and y components added
F=squareroot(x^2+y^2)


The Attempt at a Solution

Since you are given the mass and separation of these spheres, you could use the standard formula to find the attraction force between two adjacent spheres.
Let's call that F at the moment.

Now, suppose the 4 spheres are A, top Left; B top Right; C bottom Left; D Bottom Right.

Consider Sphere C.
A pulls up with force F [as calculated above.
D pulls Right with Force F
B bulls diagonally with a force less than F, because it is forther away. But you know how much further so can calculate the force.

Now just add those three forces as vectors and you have it.

Now do A, B and D
 

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