(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Given a common intersection point (3,4,5), find 3 different planes.

2. Relevant equations

None

3. The attempt at a solution

What I did is let

a_{1}x+a_{2}y+a_{3}z=a

b_{1}x+b_{2}y+b_{3}z=b

c_{1}x+c_{2}y+c_{3}z=c

3=D_{x}/D 4=D_{y}/D 5=D_{z}/D

I set D=2, therefore D_{x}=6 D_{y}=8 D_{z}=10,

I was stuck then, no matter how I did I just got a bunch of unknown.

This question is supposed to find any 3 linear equations(aka 3 planes) that satisfy the intersection point.

Well, who doesn't know how to find the intersecting point using Cramer's rule...

P/S: This question comes up in my calculus 3 question, and I have not taken any algebra course yet, so I only know the condition for Cramer's rule for a common intersection point to take place which is D not equal to 0.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Help!Given a common intersection point, create 3 different planes

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