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Homework Help: Help graph

  1. Jul 11, 2005 #1
    help plz...graph

    Here is a question i am havin a bit of trouble with.

    http://img125.imageshack.us/img125/8824/cs2rr.jpg [Broken]

    This is what i figured out:

    f'(1) must be a local max or min since hte derivativee is 0

    the second line are the vertical and horz assympotes.
    there is a vertical assymptote at x=0
    there is a horizontal assymptote at y=-4 and y=-1

    f(-2) is the point where changes concavity

    concave down -2<x<0
    Concave up x<-2 or x>0

    I am unsure of how to draw this graph. thanks for your help in advance.
    Last edited by a moderator: May 2, 2017
  2. jcsd
  3. Jul 11, 2005 #2
    Yu Just Gave All The Conditions For The Graph. Take A Min Athink About It. First Draw Your Assmytopes, Then Insert Your Critical Points And So On
  4. Jul 11, 2005 #3
    here is what i get for the graph. can someone please verify it.

    http://img77.imageshack.us/img77/7238/graph7zp.jpg [Broken]
    Last edited by a moderator: May 2, 2017
  5. Jul 11, 2005 #4
    that looks about right, i matched up the data given and ur graph...and seems kinda accurate....one thing is that....ur f(-2) doesnt seem to be a point of inflection in ur graph its just going up... without changing direction or anything...so i think u might want to fix that
  6. Jul 11, 2005 #5
    What are you trying to say here bengali babu? i dont understand how you say it seems kinda accurate and then you say that my graph just goes up wihtout changing direction. thank for ur help, but i dont get what ur trying to say. can you please clarify. thanks.
  7. Jul 11, 2005 #6
    actually, i am unsure of this....there might be more to this than i originally thought...maybe someone else cud help u, good luck :smile:
    Last edited: Jul 12, 2005
  8. Jul 12, 2005 #7
    :frown: thanks anyways bengali :smile: , hopefully someone else will be ablle to help me out.
    Last edited: Jul 12, 2005
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