# Help graph

#### punjabi_monster

help plz...graph

Here is a question i am havin a bit of trouble with.

http://img125.imageshack.us/img125/8824/cs2rr.jpg [Broken]

This is what i figured out:

f'(1) must be a local max or min since hte derivativee is 0

the second line are the vertical and horz assympotes.
there is a vertical assymptote at x=0
there is a horizontal assymptote at y=-4 and y=-1

f(-2) is the point where changes concavity

concave down -2<x<0
Concave up x<-2 or x>0

I am unsure of how to draw this graph. thanks for your help in advance.

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#### mathmike

Yu Just Gave All The Conditions For The Graph. Take A Min Athink About It. First Draw Your Assmytopes, Then Insert Your Critical Points And So On

#### punjabi_monster

here is what i get for the graph. can someone please verify it.

http://img77.imageshack.us/img77/7238/graph7zp.jpg [Broken]

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#### bengalibabu

that looks about right, i matched up the data given and ur graph...and seems kinda accurate....one thing is that....ur f(-2) doesnt seem to be a point of inflection in ur graph its just going up... without changing direction or anything...so i think u might want to fix that

#### punjabi_monster

bengalibabu said:
that looks about right, i matched up the data given and ur graph...and seems kinda accurate....one thing is that....ur f(-2) doesnt seem to be a point of inflection in ur graph its just going up... without changing direction or anything...so i think u might want to fix that
What are you trying to say here bengali babu? i dont understand how you say it seems kinda accurate and then you say that my graph just goes up wihtout changing direction. thank for ur help, but i dont get what ur trying to say. can you please clarify. thanks.

#### bengalibabu

actually, i am unsure of this....there might be more to this than i originally thought...maybe someone else cud help u, good luck

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#### punjabi_monster

thanks anyways bengali , hopefully someone else will be ablle to help me out.

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