Calculating Heat of Vaporization for Solid CO2 in Water

In summary, the heat of vaporization refers to the heat needed for a substance to transition from solid to vapor. In this problem, 125 grams of dry ice is added to 500 grams of 66 degree celsius water, resulting in a final temperature of 29 degrees celsius. This indicates that the dry ice has converted to gas, leaving the solution. The heat lost by the water is equal to the heat needed for the dry ice to sublimate, which is known as the heat of vaporization. The temperature change of the water is not relevant to this calculation.
  • #1
nsw
12
0
Help!---heat Of Vaporization

I could really use some help with this please!

125 grams of dry ice (solid CO2)is dropped into a beaker containg 500 grams of 66 degree celsius water. The dry ice converts directly to gas, leaving the solution. When the dry ice is gone, the final temperature of the water is 29 degrees celsius. What is the heat of vaporization of solid CO2?
 
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  • #2
Homework is handled on a "you show us what you've done, and we'll point you in the direction you need to go." Take a couple wild swings --- think about the initial state (dry ice + water) and the final state, and what has happened to get from initial to final.
 
  • #3
heat of vaporization

Doesn't it have to do with the Qlost=Qgain
 
  • #4
I said, "...wild swing..." For a first guess, you're not doing too badly --- at the same time, very few things don't have anything to do with Ql and Qg.

You are evaporating carbon dioxide; the specific process is transition from solid phase to vapor ("sublimation" for the anal-retentive). This process requires heat, specifically, the "heat of vaporization" you used to title the thread. What do you have available as a heat source for this process in this problem?
 
  • #5
Consider the dry ice and the water to comprise an adiabatic (closed with respect to heat) system, so that the loss of heat (defined in terms of calories) from the water equals the heat needed to sublimate the CO2 mass.
 
  • #6
Sorry, but i am still confused about this problem.
 
  • #7
ok what is Qlost & Qgain Write them in terms of mass. specific etc, Heat of sublimation etc
 
  • #8
Q=mass*specific heat*change in temp.

But how does this help me?
 
  • #9
Reread the problem: does it state anything about a temperature change?
 
  • #10
yes it does talk about temperature change
 
  • #11
What temperature change?
 
  • #12
The temperature change is of the fluid in the beaker which goes from 66 to 29 degrees celsius.
 
  • #13
How much heat is required for this temperature change?
 

What is the heat of vaporization?

The heat of vaporization is the amount of energy required for a substance to change from a liquid state to a gaseous state at a constant temperature and pressure.

How is the heat of vaporization measured?

The heat of vaporization is typically measured in units of joules per mole (J/mol) or kilojoules per mole (kJ/mol). It can also be measured in units of calories per gram (cal/g) or kilocalories per mole (kcal/mol).

What factors affect the heat of vaporization?

The heat of vaporization is affected by the intermolecular forces between molecules, the temperature and pressure of the substance, and the molecular weight of the substance.

What is the relationship between heat of vaporization and boiling point?

The heat of vaporization is directly related to the boiling point of a substance. A higher heat of vaporization means a higher boiling point, and vice versa.

How is the heat of vaporization used in everyday life?

The heat of vaporization is an important concept in industries such as chemical engineering, where it is used in the design and operation of various processes involving the conversion of liquids to gases. It is also used in everyday life, such as in cooking, where the heat of vaporization of water is responsible for the cooking process.

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