- #1
- 44
- 0
Roll a fair die twice and find the probability of at least one 4
here's what i did:
P(A) = |A|/|Ω| = (6C1*6C0+6C1*6C1)/(6C1*6C1)
And i get the answer as 42/36 and the real answer is 5/36
what did I do wrong
here's what i did:
P(A) = |A|/|Ω| = (6C1*6C0+6C1*6C1)/(6C1*6C1)
And i get the answer as 42/36 and the real answer is 5/36
what did I do wrong