Help in integration i=1/L∫Vdt || V=(6t+26)/(t^2+10t+21)

  • Thread starter cunhasb
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  • #1
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I hope anyone could give me a hand on this one...

The induced emf in a 5-henry inductor varies as V=(6t+26)/(t^2+10t+21). Recalling that current i=1/L∫Vdt, find the formula for the current i as a function of time t.

This is what I've gotten so far...

∫(6t+26)/(t^2+10t+21)=(6t+26)/(t+3)(t+7)=A/(t+3)+B(t+7)=2/(t+3)+4/(t+7) dt

i=1/5∫2/(t+3)+4/(t+7)dt
i=1/5(ln(t+3)^2+ln(t+7)^4+k...

Well should I stop here since I've gotten only the variable t on the right side of the formula or should differentiate it since they are asking for the formula of currentas a function of time t? If so... is this correct?

di/dt=1/5{[(2t+6)/(t+3)^2]+[(4t+28)/(t+7)^4)]}

Thank you again guys...
 

Answers and Replies

  • #2
Astronuc
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Sorry, I saw this one then lost it, and forgot. :blushing:

The expression for i(t) seems correct. But one would need and initial condition to solve for an integration constant, or if the limits of integration are t=0 (or to and t=t, one would hopefully have io, which could be zero if the circuit is open, or there is some constant (DC) current.

This question would be appropriate in electrical engineering or homework sections.
 

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