no there is nothing wrong with the problem and iam in what called in our country differentiation and integration 2 like calculus 3
and the original problem is from my exam {{ and i didn't solve it but I'm curious }}
given____ { int from 0 to 4 }{int from y^1/2 to 2 } cos(x^5) dx dy ____ reverse the order of integration and evaluate the resulting intgerals .
after reversing , it will be ______ x^2 cos (x^5) dx _______ and the inequalities dosent matter
#4
Vid
402
0
You reversed the order of integration. You intergrate with wrt y first, dydx.
Are you sure it was [itex] \cos(x^5)[/itex]? You really couldn't integrate that on a test. The method for reversing the order of integration is fairly simple. You first need to sketch the area of integration on a graph and then find the limits for integrating over y with x constant and then the limits for integrating over x with y constant.
#7
fantomas2005
4
0
i'm absolutely sure that it's int of x^2 cos(x^5) dx
dose anyone have any idea ??
#8
dirk_mec1
761
13
What was the original question? We've already proved that the integral you post is too difficult!