1. Sep 21, 2013 #1

   sammiyahc0

   

   The position of a particle moving in a straight line during a 10–second trip is s(t) = 3t2 − 3t + 5 cm.Find a time t at which the instantaneous velocity is equal to the average velocity for the entire trip

    

   sammiyahc0, Sep 21, 2013
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3. Sep 21, 2013 #2

   adjacent

   

   Gold Member

   Show us some attempt at least!

    

   adjacent, Sep 21, 2013
4. Sep 21, 2013 #3

   sammiyahc0

   

   s'(t)=6t-3=6(10)-3=57s instantenous velocity but I don't know how to get average

    

   sammiyahc0, Sep 21, 2013
5. Sep 21, 2013 #4

   SteamKing

   

   Staff Emeritus

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   Please don't post the same problem in different forums.
   
   See, you've confused yourself because there may be different replies in your other post.

    

   SteamKing, Sep 21, 2013
6. Sep 21, 2013 #5

   sammiyahc0

   

   I still need help.

    

   sammiyahc0, Sep 21, 2013
7. Sep 21, 2013 #6

   haruspex

   

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   Average velocity is defined as change in position divided by time elapsed.

    

   haruspex, Sep 21, 2013
8. Sep 21, 2013 #7

   Vanadium 50

   

   Staff Emeritus

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   Please use this thread: https://www.physicsforums.com/showthread.php?t=711711

    

   Vanadium 50, Sep 21, 2013

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