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The position of a particle moving in a straight line during a 10–second trip is s(t) = 3t2 − 3t + 5 cm.Find a time t at which the instantaneous velocity is equal to the average velocity for the entire trip
Average velocity is defined as change in position divided by time elapsed.s'(t)=6t-3=6(10)-3=57s instantenous velocity but I don't know how to get average