- #1

IntegrateMe

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(A) Calculate dP/dt using the chain rule, and give interpretations for each part of your calculation.

**P(θ(t)). So, dP/dt = P(θ(t))' = P'(θ(t)) * θ'(t)**

P'(θ(t)) is the average rate of change of power with respect to θ.

θ'(t) is the average rate of change of θ with respect to t.

P'(θ(t)) is the average rate of change of power with respect to θ.

θ'(t) is the average rate of change of θ with respect to t.

(B) Suppose θ(t) = arcsin(t/7 -1) + π/2. Calculate θ'(t) using the equivalent expression: sin(θ(t) - π/2) = t/7 - 1

**I just differentiated the equivalent function:**

cos(θ(t) - π/2)*θ'(t) = 1/7

θ'(t) = 1/(7*cos(θ(t) - π/2))

cos(θ(t) - π/2)*θ'(t) = 1/7

θ'(t) = 1/(7*cos(θ(t) - π/2))

(C) Suppose dP/dθ (2π/3) = 12 and θ(t) is the function in part (B). Find the change in power output between 4:30PM and 5:30PM.

**This is where I'm having trouble. I would think the "change in power output" would simply be dP/dθ, since this represents the change in power with respect to θ, but I feel as though I'm incorrect here. Any help would be awesome. Thanks!**