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**1. Homework Statement**

If [tex]ln|y| - ln|y-a| = b[/tex] find y

**2. The attempt at a solution**

[tex]ln\frac{y}{y-a} = b[/tex]

[tex]\frac{y}{y-a} = e^b[/tex]

[tex]y-e^by = -ae^b[/tex]

[tex]y (-e^b) = -ae^b[/tex]

[tex]-y = \frac{-ae^b}{e^b}[/tex]

[tex]y = a[/tex]

I know thats not right.. let me know where I went wrong