Get Help with Questions: Explaining Solutions

  • Thread starter r-soy
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In summary, The conversation is about solving two equations, the first one being y= 3- 2/x and the second one being y= (1/5) x. The solution involves basic algebraic operations such as subtracting, dividing, and taking the reciprocal. For the first equation, the solution is x= -2x/(y-3) and for the second equation, the solution is x= 5y.
  • #1
r-soy
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hi

help me in these questions

I want to explain the solution to these questions

How do we get the result ?
 

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  • #2
Your attachment may take a while to get 'approval'. Perhaps post the question in text
 
  • #3
It's pretty much basic algebra. The first equation is y= 3- 2/x and I guess the problem is to solve for x. First subtract 3 from both sides: y- 3= -2/x. Divide both sides by -2 to get (y- 3)/(-2)= 1/x. Now take the reciprocal of both sides: -2x/(y- 3)= x.

The second equation is y= (1/5) x. Okay, since x is divided by 5 and you want to solve for x, do the "opposite"- multiply both sides by 5: 5y= x.
 

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