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Help me solve this integral?

  1. Sep 18, 2008 #1
    Hello, can someone help me solve this integral? I think I need to complete the square...I've tried many other things but I don't know what else to use :confused:




    With the last one I did long division and I ended up with: x + x/ (x - 1)...so I can easily solve the first integral of X but now I can't solve the other part... :(
    Last edited: Sep 19, 2008
  2. jcsd
  3. Sep 19, 2008 #2
    Re: Integral

    Try using latex, it might be a while before we can view your image.
  4. Sep 19, 2008 #3
    Re: Integral

    I posted the image differently :)
  5. Sep 19, 2008 #4
    Re: Integral

    U-sub is the easiest on the first one, u-sub and factor actually...

    U-sub the second one too
  6. Sep 19, 2008 #5


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    Homework Helper

    Re: Integral

    you could rewrite




    if that is any easier for you.
    Last edited: Sep 19, 2008
  7. Sep 19, 2008 #6


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    Staff Emeritus
    Science Advisor

    Re: Integral

    Not "complete the square", the denominator is a cube, not a square! The substitution
    u= -x3+ 9x+ 1 works nicely.

    You need to review your long division! x2 divided by x- 1 is x+ 1+ 1/(x-1).
  8. Sep 22, 2008 #7
    Re: Integral

    Thank you so much everybody :)
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