# Help me solve this integral?

1. Sep 18, 2008

### Fiorella

Hello, can someone help me solve this integral? I think I need to complete the square...I've tried many other things but I don't know what else to use

and

With the last one I did long division and I ended up with: x + x/ (x - 1)...so I can easily solve the first integral of X but now I can't solve the other part... :(

Last edited: Sep 19, 2008
2. Sep 19, 2008

### Feldoh

Re: Integral

Try using latex, it might be a while before we can view your image.

3. Sep 19, 2008

### Fiorella

Re: Integral

I posted the image differently :)

4. Sep 19, 2008

### Feldoh

Re: Integral

U-sub is the easiest on the first one, u-sub and factor actually...

U-sub the second one too

5. Sep 19, 2008

### olgranpappy

Re: Integral

you could rewrite

$$\frac{x}{(x-1)}$$

as

$$1+\frac{1}{x-1}$$

if that is any easier for you.

Last edited: Sep 19, 2008
6. Sep 19, 2008

### HallsofIvy

Staff Emeritus
Re: Integral

Not "complete the square", the denominator is a cube, not a square! The substitution
u= -x3+ 9x+ 1 works nicely.

You need to review your long division! x2 divided by x- 1 is x+ 1+ 1/(x-1).

7. Sep 22, 2008

### Fiorella

Re: Integral

Thank you so much everybody :)