1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Help me understand the energy of a phtoton

  1. Feb 11, 2010 #1
    If the energy of single photon of electromagnetic radiation is defined by its wavelength, could it also be set equal to its potential and kinetics?(I’m probably missing something)
    Please check this statement:
    attachment.php?attachmentid=23675&stc=1&d=1265947307.jpg
    Where :
    h is planks constant
    f is frequency.
    m0 is rest mass
    M is the relativistic mass
    v is velocity


    If rest mass of electron is zero then mc2 is zero therefore the total energy must be all kinetic(right?).
    The only way I could see the kinetic energy not being zero is if somehow the relativistic mass is not zero…or maybe I got it completely wrong…?

    Thx in advance.
     

    Attached Files:

  2. jcsd
  3. Feb 11, 2010 #2

    Dale

    Staff: Mentor

    The correct relativistic expression is:

    [tex]E^2 = m_0^2 c^4 + p^2 c^2 = h^2 f^2[/tex]
    Where [itex]m_0[/itex] is the invariant mass, [itex]p[/itex] is the momentum, and the rest are as you have them above.

    The expression is general and applies for both massless and massive particles, but a photon has an invariant mass of 0.
     
  4. Feb 12, 2010 #3
    thx for response.

    even so. if p is mass times the velocity, again it comes down the mass or at least the variant mass not being equal to zero.
    maybe i'm not looking at it the right way but the variant mass of a particle being defined as
    attachment.php?attachmentid=23680&stc=1&d=1265993338.jpg
    gives the value 0 devided by zero as [tex]v\rightarrow c[/tex] and as [tex]m_0[/tex] [tex]\rightarrow 0[/tex].

    i guess the reason for my confusion is that if mass and energy are the same thing in different forms there must be a mass equivalent for a photon(right?)
     

    Attached Files:

  5. Feb 12, 2010 #4

    Dale

    Staff: Mentor

    Momentum is not mass times velocity in general. As you mention the formula you provided is not valid for photons. The general formula for momentum is de Broglie's formula:
    [tex]p=\frac{h}{\lambda}[/tex]
    where [itex]\lambda[/itex] is the wavelength.

    Which applies for both massive and massless particles.


    The term you are looking for is "relativistic mass". As you note, it is nothing more than another name for the total energy. Because we already have a perfectly good name for energy this term is generally deprecated. Usually the unqualified word "mass" refers to the "invariant mass" or "rest mass", [itex]m_0[/itex], but I tend to always explicitly say which definition of mass I am using just to avoid confusion.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Help me understand the energy of a phtoton
Loading...