Find two vectors which are perpendicular, and one of them is twice the magnitude of the other. Also their sum should be (6,8).(adsbygoogle = window.adsbygoogle || []).push({});

First of all let the coords be (x,y) and (a,b)

then the magnitude of one of them is twice the other i .e . [tex] 2 \sqrt{x^2+y^2} = \sqrt{a^2+b^2} [/tex]

also their dot product is zero

[tex] (x,y) \cdot (a,b) = 0 -> xa + yb = 0 [/tex]

also the cross product is just the magnitudes of the vectors multiplied

[tex] (x,y) \times (a,b) = 2 (x^2 + y^2) [/tex]

But somehow i cannot get the fact that they add up to 6,8 to work into this framework i have setup

Is it simpler than i think it is??

Please help!!!!! Thank you in advance!

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# Help me with cross product question!

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