Determine the instantaneous power absorbed by the capacitance

In summary, the capacitor absorbs power at an instantaneous rate and releases that power over a period of 1.39 seconds.
  • #1
Nasoomah
2
0
1. For the circuit of Figure 1, VT = 100 V, R = 5000 Ω and C = 400 μF; switch S is closed at t = 0.
a) Determine the instantaneous power absorbed by the capacitance.
b) Obtain an expression for the instantaneous power dissipated in the resistance.
c) Determine the voltage across the capacitor at time t = 1.39 s.



A 75-Ω resistance is connected in parallel with a 10-μF capacitance. Determine an equivalent series RC circuit such that the two circuits have the same impedance at an angular frequency of 1000 rad/s.
If a voltage source is connected to the parallel RC circuit as shown in Figure 2, determine the maximum energy absorbed by the capacitor.




Figure 2
Explain the graph for energy absorbed and released from a capacitor in the circuit in Figure 2.


q3: Replace the network of Figure 3 to the left of terminals ab by its Thevenin’s equivalent



q4:
For the circuit given in Figure 4, for t > 0, determine the inductor current〖 i〗_L (t).



the figure in the attachments
 
Last edited:
Physics news on Phys.org
  • #2
Welcome to PF!

Hi Nasoomah! Welcome to PF! :smile:
Nasoomah said:
the figure in the attachments

erm :redface:what attachments? :confused:
 
  • #3
[QUOTE=Nasoomah;2683904]1. For the circuit of Figure 1, VT = 100 V, R = 5000 Ω and C = 400 μF; switch S is closed at t = 0.
a) Determine the instantaneous power absorbed by the capacitance.
b) Obtain an expression for the instantaneous power dissipated in the resistance.
c) Determine the voltage across the capacitor at time t = 1.39 s.



A 75-Ω resistance is connected in parallel with a 10-μF capacitance. Determine an equivalent series RC circuit such that the two circuits have the same impedance at an angular frequency of 1000 rad/s.
If a voltage source is connected to the parallel RC circuit as shown in Figure 2, determine the maximum energy absorbed by the capacitor.




Figure 2
Explain the graph for energy absorbed and released from a capacitor in the circuit in Figure 2.


q3: Replace the network of Figure 3 to the left of terminals ab by its Thevenin’s equivalent



q4:
For the circuit given in Figure 4, for t > 0, determine the inductor current〖 i〗_L (t).



the figure in the attachments[/QUOTE]
 

What is the definition of instantaneous power absorbed by a capacitance?

The instantaneous power absorbed by a capacitance is the rate at which energy is being stored or released in a capacitor at a specific moment in time. It is measured in watts and can be calculated using the formula P = IV, where P is power, I is current, and V is voltage.

How is the instantaneous power absorbed by a capacitance different from average power?

The instantaneous power absorbed by a capacitance is the amount of power at a specific moment in time, while average power is the average amount of power over a period of time. Instantaneous power can vary greatly, while average power remains relatively constant.

What factors affect the instantaneous power absorbed by a capacitance?

The instantaneous power absorbed by a capacitance is affected by the voltage and current in the circuit, as well as the capacitance of the capacitor. The power absorbed will increase as the voltage and current increase, and also as the capacitance increases.

How can the instantaneous power absorbed by a capacitance be calculated?

The instantaneous power absorbed by a capacitance can be calculated using the formula P = IV, where P is power, I is current, and V is voltage. This formula can also be applied to specific components in a circuit, such as a capacitor, by using the current and voltage values specific to that component.

Why is it important to calculate the instantaneous power absorbed by a capacitance?

Calculating the instantaneous power absorbed by a capacitance is important because it helps us understand how much energy is being stored or released in a capacitor at a specific moment in time. This information is useful for designing and troubleshooting circuits, as well as determining the overall efficiency of a circuit.

Similar threads

  • Engineering and Comp Sci Homework Help
Replies
10
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
26
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
6
Views
1K
  • Engineering and Comp Sci Homework Help
Replies
16
Views
958
  • Engineering and Comp Sci Homework Help
Replies
4
Views
2K
  • Engineering and Comp Sci Homework Help
Replies
8
Views
4K
  • Engineering and Comp Sci Homework Help
Replies
16
Views
3K
  • Engineering and Comp Sci Homework Help
Replies
29
Views
4K
  • Engineering and Comp Sci Homework Help
Replies
8
Views
3K
Back
Top