Hey all, Grade 11 physics assignment due tmrw and im having some trouble. Any help would be appreciated. So here it is: A candle of height 4.8 cm is placed 38.6 cm in front of a converging mirror with curvature 30.2 cm. What is the height of the image? Heres what I have: 1/f = 1/Di + 1/ Do so..... 1/15.1 = 1/Di + 1/38.6 so Di=2.56 then.... Hi/Ho = -Di/Do so............ Hi/4.8 = -2.56/38.6 so Hi=-.32 where: Ho= Height of object (candle) Do= Distance of object Di= Distance of image Hi= Height of image f=focus (which i have calculated to be 15.1) The answer i get is -.32cm which doesn't seem right to me. Am i doing something wrong? Missing something?? As well.... a totally unrelated question- When looking at interference patterns of water through 2 openings, if the second nodal line is formed at an angle of 50 degrees, will n=1 or n=1/2? Thanks for any help!!!