Help Needed: Solve Cube Root Question ASAP

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can someone help me solve this question as fasd as possible??
im really headache wif it...
thx~~

determine the 3 cube roots of 3-i over 3+i giving the result in modulus argument form,express the principal root in the form a+Jb
 

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  • #2
hello..anyone can help me out??
 
  • #3
can someone help me solve this question as fasd as possible??
im really headache wif it...
thx~~

determine the 3 cube roots of 3-i over 3+i giving the result in modulus argument form,express the principal root in the form a+Jb

Do not bump your post after only 16 minutes. It is unreasonable to expect fast help all the time here on the PF.

Also, you must show your attempt at a solution before we can be of help. Show us how you would go about simplifying the complex fraction that you are describing...
 
  • #4
First off, you're going to want to calculate (3 - i)/(3 + i), to get it in the form a + bi. After that, you should calculate the polar form of this complex number, r(cos[itex]\theta[/itex] + i sin[itex]\theta[/itex]). After that, you can use DeMoivre's Formula to find a cube root, which says that
[tex](r(cos\theta + i sin\theta))^{1/n} = r^{1/n}(cos(\theta/n) + i sin(\theta/n))[/tex].
 

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