Re-Arranging Formula for Creep Rupture Time Calculation | Helpful Tips"

[hoola]

Homework Statement

I am trying to re-arrange the following formula so I can work out the creep rupture time of a material, using the Larson-Miller parameter (LM)

Homework Equations

LM = T (C + log tr)

where : C = constant ( usually of the order of 20 )
T = the temperature in Kelvin
tr = rupture time in hours.

The Attempt at a Solution

I am struggling with the re-arrangement of the "log" bit. Any help would be very much apppreciated.

 

[Hootenanny]

Hi hoola and welcome to PF,

What is the inverse of a logarithm?

 

[Moetasim]

I understand the importance of being able to manipulate and rearrange equations in order to solve for a desired variable. In this case, the Larson-Miller parameter (LM) is used to calculate the creep rupture time of a material at a given temperature. The equation provided is LM = T (C + log tr), where C is a constant and tr is the rupture time in hours.

To rearrange this equation, we can start by dividing both sides by T, giving us LM/T = C + log tr. Then, we can subtract C from both sides, resulting in LM/T - C = log tr. Finally, we can take the inverse of the logarithm on both sides, giving us tr = 10^(LM/T - C).

This rearranged equation allows us to solve for the rupture time (tr) by plugging in the values for LM and T. It is important to note that the value of C may vary depending on the material being studied, so it is crucial to use the correct value for accurate calculations.

I hope this explanation helps in understanding the rearrangement of the formula for creep rupture time calculation. If you have any further questions, please do not hesitate to ask.